I need to find the equivalent resistance and the current at I

I'm not sure where to start, I need to use Thevenins theorem? And it's a Wheatstone bridge?

If I take out the diagonal 3ohm resister which represents the load (I think this is the first step?) I'm not sure what to do next?

Please help!

First, you have to group the resistors together.
For the two 3ohm resistors on the right and on the top. They are equivalent to one 6ohm resistor as they are connected in series. Then this 6ohm resistor is in parallel with the remaining 3 ohm resistor. Group it into a 2ohm resistor.This 2ohm resistor is in series with the 2ohm resistor at the bottom. Group them into a 4ohm resistor.The 4ohm resistor is now in parallel with the 1ohm resistor. Group them into a (4/5)ohm. This resistor is now in series with the remaining 5ohm and 2ohm resistor.

Then you can find the equivalent resistance. Use V=IR for finding the current. Hope that I do not do the calculations wrong.

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Going to face the Hong Kong Advanced-Level Examination which is believed to be the most difficult AL exams in the world this year. I hope good results can be achieved.