I am lost as to how to solve this problem, i have tried using cos(62.5) to find horizontal and sin(62.5) to find altitude, both where wrong, and for part A i have no idea what to do, please help

A rocket is launched from rest and moves in a straight line at 62.5 ° above the horizontal with an acceleration of 55.0 m/s2. After 23.0 s of powered flight, the engines shut off and the rocket follows a parabolic path back to earth. Find the time of flight from launch to impact.

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What is the maximum altitude reached?

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What is the horizontal distance between the launch pad and the impact point?

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Hi juggalomike
find the distance traveled when the power is on using kinematics, then use trigonometry to find the altitude

So, the time of flight from launch to impact = 23 seconds + t
When the engines shut off, the velocity in y-direction = 0. Find t.


total horizontal distance = horizontal distance when power is on + horizontal distance of parabolic motion

So does that meen when the power shuts off thats the max altitude? i as under the impression that due to the acceleration from the thrusters it would continue to rise until gravity reduced the velocity to 0

nvm, figured it out thanks