Light of wavelength 200 nm shines on an aluminum surface with 4.20 eV of work function is required to eject an electron from its surface.

What is the kinetic energy of the fastest ejected electrons?

What is the kinetic energy of the slowest ejected electrons?

What is the stopping potential for this situation?

What is the cutoff wavelength for aluminum?

Photoelectric effect - Wikipedia, the free encyclopedia
Electronvolt - Wikipedia, the free encyclopedia

E[eV]=1240/L[nm]
energy E and wavelength L of a photon.
In our case
E=1240/200=6,2 eV.

The kinetic energy of the fastest ejected electrons is 6,2-4,2=2,0 eV.
The kinetic energy of the slowest ejected electrons is 0 eV because
the work function in our case may be greater than 4,2 eV. When it
reaches 6,2 eV the kinetic energy will be 0.
The stopping potential is 4,2 eV for this situation which is the minimum
energy required to remove a delocalised electron from the surface.
The cutoff wavelength is
L=1240/4,2=295 nm.

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