Hi!
Is there a way to calculate current velocity of fluid in a pipe with a pressure added? (Without side-effects like turbulence) Like a water pump... adds some pressure to get the water moving.
I read about Bernoulli's principle, but it didn't seem to apply on this situation about higher velocity means lower pressure, but did seem to apply on the way car spoilers work.

hi,

Velocity pressure is (1/2)pv^2 where p will be the density.

When you mention Bernoulli be careful that your not confused here, increased velocity pressure = lower static pressure, but this does not imply that the resistance will be lower, the resistance will be higher if you increase the velocity pressure, i'm finding it hard to try to explain, its very complicated.

Let me put it another way and i hope i'm not going off topic here.

If you estimated the volume with a resistance.

lets say you wanted 0.5m^3 of liquid a sec to pass through the pipe and you estimated the static pressure resistance to be 1000 Pa for the total resistance in the pipe system. Lets say you under estimated the total resistance and the true resistance was 1100 Pa.

You would have Sq-rt (1000/1100)=0.9534

so the volume of liquid would be 0.5*0.9534 =0.4767m^3/s

Thanks for the help!

My pleasure, thats the concept of the forum.

Another point i would like to mention is, do you know how to work the velocity out?

Use either

Darcy–Weisbach or Hagen–Poiseuille equation

Hagen?Poiseuille equation - Wikipedia, the free encyclopedia

I think the Darcy–Weisbach will be the one to use.